Ch
17.1 #3
A flowerpot is
knocked off a balcony 20.0 m above the sidewalk and falls toward an
unsuspecting 1.75 m tall man who is standing below. How close to the sidewalk can the flower pot
fall before it is too late for a warning shouted from the balcony to reach the
man if the mans reaction time is 0.300 seconds.
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v = Dx / Dt 343
= (20-1.75)/Dt tsound = 0.0532 sec treact = 0.3 sec tneed = 0.353 sec |
d = ½
at2 (20–1.75)
= ½9.8t2 tdrop = 1.93 sec |
1.93 s–0.353 s = 1.58 s So the warning must be given within 1.58 sec for
the man to respond in time. |
The distance covered in 1.58 seconds is d
= ½ a t2 d
= ½ 9.8 1.582 d = 12.2 m |
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So the pot is 20
– 12.2 meters above the ground = 7.82 meters |
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Ch
17.2 class
We’ve decided we
want to create a sound wave in class that has displacement amplitude of 1
micron (10-6 m). We don’t
want the pressure amplitude to be greater than 2.00 N/m2. What is the minimum wavelength?
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ΔPmax = ρ
v (ω) smax ΔPmax = ρv(2πv/λ) smax λ = 2π
ρ v2 smax
/ΔPmax λ = 2π(1.17)
3432 10-6 / 2 λ = 0.432 meters |
ω = 2π f ω = 2π(v/λ) note: density of dry air at 0°C is 1.29 kg/m3, but
then v = 331 m/s |
Ch
17.3 baby
You are in a movie
theater. The sound in one scene is at
approximately 80.0 dB. There is a baby
in the next row that crys at 76 dB because of this
loud noise. (a) What sound intensity do
you hear? (b)What is the sound level in
dB?
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β = 10 log (I / Io) 80 = 10log(Imovie/10-12) Imovie = 10 x 10-5 W/m2 |
β = 10 log (I / Io) 76 = 10log(Icry/10-12) Icry = 3.98 x 10-5 W/m2 |
(b) β = 10 log (I / Io) β = 10log(13.98 x 10-5 /10-12) β = 81.5 dB |
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(a) I = Imovie + Icry
I = 13.98 x 10-5 W/m2 |
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Ch
17.4 car
At
a raceway you hear the frequency of a racecar as 600 Hz approaching toward you.
After the car passes, the observed frequency of the siren is 400 Hz. What is
the speed of the car?
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From lecture notes f’ / v’ = f / v Toward: v ’ = v + vo Away: v ’ = v - vo |
Toward: 600/(340+vo) = f / 340 Away: 400/(340-vo) = f / 340 |
600/(340+vo) = 400/(340-vo) 1.5(340-vo) = 340+vo 170
= 2.5 vo
vo = 68.0 m/s |
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Ch
17.4 #47 A supersonic jet
traveling at Mach 3.00 at an altitude of 20000 m is directly over a person at
time t = 0. (a) How long will it be before the person encounters the
shock wave? (b) Where will
the plane be when it is finally heard? (Let speed of sound in air be 335 m/s.) |
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sin q = v / vs sin q = 335 / 3(335) q = 19.5° |
tan q = h / x tan
19.5° = 20000 / x x = 5.66 x 104 meters |
v = Dx /
Dt 3(335) = 5.66 x 104 / Dt t = 56.3 sec |
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Ch
17.5 #49
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Only two
recording channels are required to give the illusion of sound coming from any
point located between two “stereo” speakers.
At the time of recording if the same signal is recorded in both
channels, a listener will hear it coming from a single direction halfway
between the two speakers. Each of the
eight singers during the “Do-Re-Mi” recording from The Sound of Music ( |
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If the source is to the left at angle θ from the direction
you are facing, the sound must travel an extra distance, d sinθ, to reach your right ear as shown, where “d” is
the distance between your ears. |
v = d sinθ / Δt 343 = 0.19sinθ/210x10-6 θ = 22.3° |
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